Legacy ImageMagick Discussions Archive

Hi Bonzo, looking at the version string you are absolutely right. I should have noticed that. Just wondering where the (nearly) up-to-date timestamp comes from. Obviously it fooled me... Version: ImageMagick 6.7.7-10 2017-05-26 Is the timestamp related to the distros build date and not the ...

Hi, looks to me like this issue came up again, I am using ImageMagick on Linux Mint 17.2: Version: ImageMagick 6.7.7-10 2017-05-26 Q16 http://www.imagemagick.org Copyright: Copyright (C) 1999-2012 ImageMagick Studio LLC Features: OpenMP strokewidth = 2 works fine and produces a proper rectangle ...

Hi magick,

As usual: thanks for the fast fix - ImageMagick 6.7.2-9 2011-09-23 on Windows XP works as expected.

Best, Andreas

I am using ImageMagick 6.7.2-8 2011-09-23 Q16 on Windows XP. When rotating images I get torn images (black stripes) for a certain range of angles. I also had a couple of crashes but they seem not to be reproducible. convert rose: -rotate 45 rotate45.jpg -> good convert rose: -rotate 46 rotate46.jpg ...

Hi magick,

This makes everybod happy: XNView, djv_view happy and me. Thanks a lot!
Andreas

Hi magick, thanks for your reply! Your posting suggests that perhaps one of the programs you listed may not read and / or write DPX images properly, however you did not specifically identify that the problem is with ImageMagick. XNView never let me down in the past with DPX files and I find it a bit ...

Hi all, not sure this is a bug or because of an error I do... I try to annotate text to 10 bit DPX images but getting very different results when displaying them in the programs listed below (all run under Windows XP). I am using ImageMagick 6.7.2-8 2011-09-23 Q16 under Windows XP to create the DPX ...

Hi Fred, I got me the official ASC specs in the meantime and Wikipeda is right: The input value, slope, ranges from 0.0 (constant output at Offset) to less than infinity ... out = in * slope 0 ≤ slope < ∞ Since I need to stay conform with the ASC standards: no more need to fiddle around. Thanks and b ...

Hi Fred, Standard CDL does not seem to support slope values less than 0 (though I suppose it could be made so, i.e. -1 to 1). See http://en.wikipedia.org/wiki/ASC_CDL "s is slope (any number 0 or greater, nominal value is 1.0)" you are right, will try to find out if Wikipedia is correct here ...

Hi all, I am trying to use ASC CDL to a) invert an image (negative) b) removing all color (b&w negative) c) I have to use CDL although I know there are other ways ;-) this is my main code: convert -cdl cdl_Invert.txt rose: rose_invert.jpg and here is cdl_Invert.txt: <?xml version="1.0" encoding="UTF ...

Anthony, I thought you were taking about reducing images from 10bit to 8bit not reducing number of colors. no, that´s a misunderstanding. The question is: is the image content of the 10bit DPX really 10bit or only 8bit? In the meantime I found something which might probably work for me, will have to ...

Anthony, I would like to see some image processing operators for generating histograms and other plots based on image data of any size, but that is on a long list of 'wishes, wants and desires; :-( But at least you are not alone :) But what you probably want is NOT the image, but the text comment ...

Thanks again Anthony will give it a try. On a slightly different topic: when I "histogram" a 10bit (DPX) image with convert orig10bit.dpx -define histogram:unique-colors=false histogram:orig10bit.dpx_h.gif the resulting GIF is 256x100 pixels. I would have expected a width of 1024 having one pixel ...

Dear Anthony,

thanks for the fast reply. I guess I somehow understand what you mean but can you give me a clue if this can be done with ImageMagick?

Thanks, Andreas

Hi all, my problem is the following: I have to check within 10bit DPX files if the image content had gone through an 8bit bottleneck before. bitdepth ( identify -format %z filename ) will tell me that my DPX file is a 10bit container and identify -format %k filename would give me the number of ...