Legacy ImageMagick Discussions Archive

Well, I solved it, but it's a little cumbersome. Since I wasn't getting any response from the function, I took a different approach that you guys kind of touched on. Here's my solution: 1) Convert to grayscale 2) Convert back to RGB 3) Run a histogram export (since R=G=B), there is a max of 256 data ...

Thanks. I'm still not getting a response, but I'll keep working on it and let you know if it ever works.

Just figured there was an easier way to just find the "maxbright" pixel (or max R, max G, max B).

News to follow...

Thanks. I tried it and didn't get any result like I anticipated. In the VB world, I typically compose like this: objMi.Convert "-profile", "C:\ColorMatchRGB.icc", myimagename, "-sample", "800x", "PNG32:C:\newimage.png" or imagedata = objMi.Identify("-units", "PixelsPerInch", "-format", "%x %y %w %h ...

Yes, as long as the grays are within the RGB range (0-255,0-255,0-255)). Let me explain this a little further. I print full-color designs on shirts. Shirts print with CMYK inks (for all intents and purposes, it could be RGB inks). Since white is the absence of all colors in CMYK colorspace (0,0,0,0 ...

No. I care:

1) ANY white (within 2%). ANY white at all.
2) ALL Black (within 2%). Completely black.
3) not conditions 1 or 2.

My source images will never be in grayscale. They'll always be RGB PNGs, even if they're all white or all black.

Thanks so much for the response. Your concept checks out, but admittedly don't know the IM commands (even without Visual Basic). Basically, I need: If MaxBright <0.02 then All Black (and exit routine) else if MaxBright >0.98 then Contains White (and exit routine) else If MaxBright >=0.02 and ...

First, let me apologize for dropping this conversation...6 years ago. I got pulled off the project and had not been reassigned until now. I'm sorry to re-open this thread, but in response to Fred's response, if I understand the theory correctly, if 100% of pixels are black, the mean is 0. ALL BLACK ...

Well, the good thing is that thanks to snibgo, I got some of this working in Windows. THANK YOU. However, what I'm trying to do is recreate what snibgo does here http://www.imagemagick.org/discourse-server/viewtopic.php?f=1&t=18497 THIS image: https://dl.dropboxusercontent.com/s/5a88lfz0s6z1gfv ...

Thanks for the adjustment, but it's just not working. I copied & pasted your code exactly and it's still throwing all kinds of errors. I think I need to find another path unless you see something obvious. Otherwise, I truly appreciate your input, but I don't want you to waste your time on it ...

I'm using 6.8.8-10 Q8 64. I couldn't get this to work in the Windows cmd console. I'm going to have to find a different path...maybe a crop/wave or some other mix. It's kicking out a ton of errors and I've already spent 2 full days trying to get it to work. Oh well. Thanks, though! convert mug.png ...

I am unable to install the Cygwin package, unfortunately (not allowed). In the meantime, though, if I follow that example script, I'm still having a little problem encoding it with VB. convert rose: -background black -gravity south -splice 0x8 \ \( +clone -sparse-color barycentric '0,0 black 69,0 ...

Hello all. I need to wrap an image (roughly 8" x 4") around a image of a mug. Of course, Fred's Cylinderize function would work great; however, I don't work with UNIX/MAC/LINUX, and cylinderize is not a valid argument in a standard IM deployment. I am leveraging IM in Windows 7 through MSAccess ...

Guys, thank you so much for your reply. Admittedly, this is way above my head, so let me ask if I'm interpreting this correctly: 1) There is a command within IM that will compare every pixel within an image to, say, black CMYK(0,0,0,100)/RGB(0,0,0). 2) I can extract from said analysis the maximum ...

Hello, I am trying to determine if EVERY pixel within an artpiece is within, say, 1% of solid black (in RGB and CMYK). Conversely, if all pixels are within 1% of solid white. Ultimately, I'd like to analyze an image to know if the creator intended for it to be solid black or solid white. What does ...