Legacy ImageMagick Discussions Archive

Hello, I found a workaround for the problem described above. I use poppler to convert the PDF to some image format and then process this new image with IM7. Here is the bash code: file="some.pdf" tmp_type="png" tmp_file="/tmp/pdftoppm_some" # note that there is no filename extension result="result ...

Hello, thanks for the reply! It is probably in a font which is neither embedded on the PDF nor installed on your computer. I had thought of something similar, but the file is displayed correctly in a PDF viewer on the same computer. I ran "pdffonts" on said PDF, with the following result: pdffonts ...

Hello, when I convert a PDF file, a specific line becomes this . The rest of the text is unaffected. This behaviour does not occur with any other PDF file (so far). The line does not contain special characters or similar. It says "Senior Vice President, Oracle University". Unfortunately, I can not ...

Hello, @fmw42: Sorry, I had overlooked that it was not made clear which approach I actually use. I'm using Geemack's approach from this thread. So if you are making a JPG output, then you must flatten your processing over some background color or image, otherwise the JPG will replace any ...

Hello, I have an additional question and I'm unsure if I should open a new thread. When I convert images which have a transparent background to jpgs, the background turns black. (As can be seen here ). That seems to be a very common problem and I have also found some approaches and explanations in ...

Hello,
the end result can be seen in this thread.

Best regards
AVoeee

Hello, -rotate "%[fx:t*(atan(((u.w/u.h)-(v.w/v.h))/(1-(u.w/u.h)*(v.w/v.h)))*180/Pi)]" \ The next line uses the formula you've written to rotate just the watermark image. That happens because I multiplied your formula by "t", which is the position of the image in the stack. The main input image is ...

Hello, thanks for your reply. I tried to follow your hints and wrote this code: wmark="watermark.png" file="some.pdf" result="result.jpg" rotation="%[fx: ratioUI=u.w/u.h; ratioWM=v.w/v.h; atan((ratioUI-ratioWM) / (1-ratioUI * ratioWM)) * 180 / Pi]" magick -background none -density 300 "$file ...

Hello, I have now switched to IM7. I am using ImageMagick 7.0.7-22 Q16 x86_64. However, I am still perplexed how to perform the calculation. "atan" returns angles in radians but "-rotate" needs degrees. Thanks for pointing this out. I'm now converting the radians to degrees via "* 180 / Pi". u.w and ...

Hello,
thanks for the replies.

I will try to switch to IM7 next week.

Best regards
AFoeee

Hello, first of all: thanks for the reply! An answer to a similar question is at https://www.imagemagick.org/discourse-server/viewtopic.php?f=1&t=33414 Unfortunately, this is my own thread. Although I am very grateful for the answers there, my current question was not answered. To briefly explain ...

Hello, I'd like to place a watermark over a number of images. Since the dimensions of these images vary, but the watermark should always have the maximal possible size at constant proportions, I have to calculate the perfect angle for the resizing. (It should look like that . Not like that .) I use ...

Hello, @GeeMack: I'm sorry, I've overlooked that you had revised your post. Thanks for the answer! The angle i was looking for can apparently be calculated by: ratio1 = pic1_width / pic1_height ratio2 = pic2_width / pic2_height angle = atan ((ratio1 - ratio2) / (1 - ratio1 * ratio2)) A complete ...

Hello, I'd like to place a watermark diagonally over a number of pictures. The width and length of these pictures differ and some might even be smaller than the watermark itself. This will be used inside a script, in which the user can choose from different options like "horizontal", "vertical ...

Hello, is there a way to access the dimensions of an image which is outside of an Image Stack while you're inside of an Image Stack? Here is my specific case: I want to place a picture over another picture. The overhead image may be rotated, but it should always scaled so that it has the maximum ...