Windows equivalent of: -fill "black(25%)" -colorize 100

[josephs]

Hi everyone,

Im using Windows Shell with ImageMagick-6.9.3-Q16-HDRI.

Can someone help me convert the following to equivalent windows code:

-fill "black(25%)" -colorize 100

I got this working as expected:

-fill black -colorize 100%%

...but I need to make the black partially transparent. I attempted this but with error:

-fill "black(25%%)" -colorize 100%%

Any help is appreciated.

[fmw42]

There are no shades of black, only shades of gray. In gray shades, black is gray(0) or gray(0%), though you can use the color name black.

So to make 25% opaque gray between black and white use the following.

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-fill "gray(25%)" -colorize 100

the 100 does not need %. If in bat file, then

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-fill "gray(25%%)" -colorize 100

Note that -colorize will not add transparency, that is, the following does not work to make 25% transparent black (alpha values are only expressed as fractions. See https://www.imagemagick.org/script/color.php

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-alpha set -channel rgba -fill "graya(0,0.25)" -colorize 100

So if you want transparent black, then you must adjust the alpha channel after creating black.

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-fill "black" -colorize 100 -alpha set -channel a -evaluate set 25% +channel

Double the % to %% if in a .bat file

EDITED above.

[fmw42]

See changes above

[josephs]

Thanks Fred. The last snippet you provided works, but it does not account for transparent hole in the image. I am working with a image similar to a picture frame, with border all around edges and inside is transparent. The result I get is perfect except it fills in the hole in the image. Im not sure if that means I need to take a different approach.

[josephs]

Just got it to work. Here is what I worked:

-fill "black" -colorize 100 -evaluate set 25%% +channel

[fmw42]

That is not correct if you want transparency. It is making a 25% gray image with no transparency. It is the same as just

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-fill "gray(25%%)" -colorize 100

[josephs]

Your right. I took a closer look at the image. It fix the issue with the hole in the image, but as you said there is actually no transparency.

[fmw42]

Perhaps you should provide your full command line and explain if you want transparency or not.

[josephs]

Here is the image I am working with: https://drive.google.com/file/d/1hbqP8e ... sp=sharing
The black part of the image is transparent.

The is the full command I am using: -fill "black" -colorize 100 -alpha set -channel a -evaluate set 60%% +channel

and here is result:
https://drive.google.com/file/d/1-7rJj9 ... sp=sharing

[snibgo]

You haven't said what you are trying to do. You have an image, with an opaque picture frame, surrounding a transparent rectangle. Do you want to change the transparent pixels, or all pixels, or what?

[fmw42]

You have not give the full command line starting with convert showing your input and output images. So we really do not know what you are trying to do nor why?

[josephs]

convert frame.tiff -fill "black" -colorize 100 -alpha set -channel a -evaluate set 60%% +channel frame2.tiff

I am trying to get the frame/border in frame.tiff filled black with about 60% transparency. The above code works except, it also fills in the inner part of the frame and that I dont want.

[fmw42]

If you provide your input image, we can probably help more. Does the input have transparency? Can you create a binary mask that corresponds to just the border that you want to add transparency?

[josephs]

Input image: https://drive.google.com/file/d/1hbqP8e ... sp=sharing
Output image: https://drive.google.com/file/d/1-7rJj9 ... sp=sharing

Yes, the input has transparency only inside of the frame. I can create a mask. I will work in that direction.

Thank you.

[fmw42]

The interior of your frame.tif is already transparent. So I am not sure what you want to do. What do you expect to happen in the middle?

If you want to change the border transparency and keep the center fully transparent, then just multiply the alpha channel of the image by 0.6.

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convert frame.tif -channel a -evaluate multiply 0.6 +channel result.tif