Error When trying to convert an emz file to a jpg in several
Posted: 2008-11-13T08:03:56-07:00
Hi,
In the past I was able to convert an emz file to a jpg one... and it is know failing.
I was first unzipping this file and then converting the result to jpg.
The original file is:
http:\\thierry.paret.free.fr\02000001_02000001.emz
The unzip file is:
http:\\thierry.paret.free.fr\02000001_02000001.emf
the convert command is:
convert.exe -compress LZW -quality 85 ".\images\02000001_02000001.emz" ".images\02000001_02000001.jpg"
My Call stack is:
convert.exe!_fstat64i32(int fildes=16384, _stat64i32 * buf=0x010c98b0) Line 93 + 0x53 bytes C
convert.exe!GetBlobSize(const _Image * image=0x01061998) Line 1193 + 0x34 bytes C
convert.exe!OpenBlob(const _ImageInfo * image_info=0x0105d858, _Image * image=0x01061998, BlobMode mode=ReadBinaryBlobMode, _ExceptionInfo * exception=0x003c7ab8) Line 2415 + 0x9 bytes C
> convert.exe!SetImageInfo(_ImageInfo * image_info=0x0105d858, MagickBooleanType rectify=MagickFalse, _ExceptionInfo * exception=0x003c7ab8) Line 3690 + 0x16 bytes C
convert.exe!ReadImage(const _ImageInfo * image_info=0x01058f28, _ExceptionInfo * exception=0x003c7ab8) Line 449 + 0x12 bytes C
convert.exe!ReadImages(const _ImageInfo * image_info=0x01058f28, _ExceptionInfo * exception=0x003c7ab8) Line 883 + 0xd bytes C
convert.exe!ConvertImageCommand(_ImageInfo * image_info=0x01058f28, int argc=7, char * * argv=0x0105d068, char * * metadata=0x00000000, _ExceptionInfo * exception=0x003c7ab8) Line 560 + 0xd bytes C
convert.exe!main(int argc=7, char * * argv=0x003c4628) Line 122 + 0x17 bytes C
convert.exe!__tmainCRTStartup() Line 327 + 0x19 bytes C
convert.exe!mainCRTStartup() Line 196 C
kernel32.dll!7c817067()
[Frames below may be incorrect and/or missing, no symbols loaded for kernel32.dll]
convert.exe!Fax3Decode2D(tiff * tif=0x0065006c, unsigned char * buf=0x0070002c, int occ=7274610, unsigned short s=99) Line 299 + 0x421 bytes C
Any Idea?
Thanks
Thierry
In the past I was able to convert an emz file to a jpg one... and it is know failing.
I was first unzipping this file and then converting the result to jpg.
The original file is:
http:\\thierry.paret.free.fr\02000001_02000001.emz
The unzip file is:
http:\\thierry.paret.free.fr\02000001_02000001.emf
the convert command is:
convert.exe -compress LZW -quality 85 ".\images\02000001_02000001.emz" ".images\02000001_02000001.jpg"
My Call stack is:
convert.exe!_fstat64i32(int fildes=16384, _stat64i32 * buf=0x010c98b0) Line 93 + 0x53 bytes C
convert.exe!GetBlobSize(const _Image * image=0x01061998) Line 1193 + 0x34 bytes C
convert.exe!OpenBlob(const _ImageInfo * image_info=0x0105d858, _Image * image=0x01061998, BlobMode mode=ReadBinaryBlobMode, _ExceptionInfo * exception=0x003c7ab8) Line 2415 + 0x9 bytes C
> convert.exe!SetImageInfo(_ImageInfo * image_info=0x0105d858, MagickBooleanType rectify=MagickFalse, _ExceptionInfo * exception=0x003c7ab8) Line 3690 + 0x16 bytes C
convert.exe!ReadImage(const _ImageInfo * image_info=0x01058f28, _ExceptionInfo * exception=0x003c7ab8) Line 449 + 0x12 bytes C
convert.exe!ReadImages(const _ImageInfo * image_info=0x01058f28, _ExceptionInfo * exception=0x003c7ab8) Line 883 + 0xd bytes C
convert.exe!ConvertImageCommand(_ImageInfo * image_info=0x01058f28, int argc=7, char * * argv=0x0105d068, char * * metadata=0x00000000, _ExceptionInfo * exception=0x003c7ab8) Line 560 + 0xd bytes C
convert.exe!main(int argc=7, char * * argv=0x003c4628) Line 122 + 0x17 bytes C
convert.exe!__tmainCRTStartup() Line 327 + 0x19 bytes C
convert.exe!mainCRTStartup() Line 196 C
kernel32.dll!7c817067()
[Frames below may be incorrect and/or missing, no symbols loaded for kernel32.dll]
convert.exe!Fax3Decode2D(tiff * tif=0x0065006c, unsigned char * buf=0x0070002c, int occ=7274610, unsigned short s=99) Line 299 + 0x421 bytes C
Any Idea?
Thanks
Thierry