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output file name
Posted: 2010-09-27T14:07:11-07:00
by rrodriguez
Hi,
In a convert command, is it possible to add a stub to the output file names related, for instance with its sizes?
For instance: having a folder with some 200 files, image001.tiff to image200.tiff, I would like to get image001w800.png to image200w800.png.
Thanks!
Re: output file name
Posted: 2010-09-27T15:11:59-07:00
by fmw42
see
http://www.imagemagick.org/script/comma ... 7tj5d6#set
convert rose: -set filename:mysize '%wx%h' 'rose_%[filename:mysize].png'
You should be able to sue "%w" only if you want.
But note you are creating a new file, not just renaming it. Some one can correct me if I am wrong about this latter part.
Re: output file name
Posted: 2010-09-27T22:00:44-07:00
by anthony
See output filename percent escapes...
http://www.imagemagick.org/Usage/files/#save_escapes
And yes convert created (or silently replaces) the file of the filename of the name given (or calculated).
"mogrify" is a limited type of "convert" command that replaces the input file with the processed file, unless directed to use a different output directory or suffix.
Re: output file name
Posted: 2010-09-28T14:54:07-07:00
by rrodriguez
Thanks! I am able to convert a single file following your messages and the links included, but I'm not able yet to understand how do the same with the whole content of a given folder. Let's say I've a folder with n pictures, image_1.tiff to image_n.tiff and want to get image_1_800x600.png to image_n_800x600.png. I am able to transform one file, for instance:
convert P1020159w1000.JPG -set filename:mysize '%wx%h' 'P1020159w1000_%[filename:mysize].png'
But, please, what is the right syntax to transform and add that text stub each and all files in a given folder?
I'm clearly failing at understanding how to reference a series of files.
Thanks for your help!
Ricardo
Re: output file name
Posted: 2010-09-28T15:02:25-07:00
by lwhistler
rrodriguez wrote:
But, please, what is the right syntax to transform and add that text stub each and all files in a given folder? I'm clearly failing at understanding how to reference a series of files.
If you are on Linux - such as Ubuntu - use an
executable bash script and run the convert command in a loop. The code below is untested and there might be syntax errors, but it should get you started on looping through files in a folder.
file.sh
Code: Select all
#!/bin/bash
for image_file in *.JPG
do
convert $image_file -set filename:mysize '%wx%h' '[filename:mysize].png'
done
Re: output file name
Posted: 2010-09-28T16:11:07-07:00
by rrodriguez
Thanks!
I've read a number of references talking about sh scripts, but as far as I understand, it must be possible to reference a bunch of files by using just ImageMagick commands. But I don't know how neither!
As for your proposal: I'm not able to pass $image_file as stub for the first part of the output file. It reads now:
Code: Select all
#!/bin/bash
for image_file in *.JPG
do
convert $image_file -set filename:mysize '%wx%h' '$image_file_%[filename:mysize].png'
done
And I get:
Code: Select all
GMXUX-Ricardo-Rodriguez:cumpleCaiCai2010 rrodriguez$ ls -l *.png
-rw-r--r-- 1 rrodriguez staff 1851726 29 sep 01:07 $image_file_1333x1000.png
-rw-r--r-- 1 rrodriguez staff 2302865 29 sep 01:07 $image_file_1498x1000.png
-rw-r--r-- 1 rrodriguez staff 977684 29 sep 01:07 $image_file_750x1000.png
Just one file for each size. Of course each of them only has the content of the last transformed picture.
Please, do you know how must I modify the convert line to pass the name of each original file (image_file) to the output file name?
Thanks!
Re: output file name
Posted: 2010-09-28T16:51:51-07:00
by fmw42
This works for me. I think the missing thing was the brackets.
Here I have 3 files in directory test1 and none to start in directory test2. I take the files from test1 and rename them into test2
lena.jpg
lena2.jpg
lena3.jpg
#!/bin/bash
cd test1
filelist=`ls | grep '.jpg'`
for image_file in $filelist
do
convert $image_file -set filename:mysize "%wx%h" ../test2/${image_file}_%[filename:mysize].png
done
results in
lena.jpg_256x256.png
lena3.jpg_128x128.png
lena2.jpg_128x128.png
in test2
Re: output file name
Posted: 2010-09-28T17:14:17-07:00
by rrodriguez
Brackets in, quotation marks out! Following the last post by fmw42, this also works for me now:
Code: Select all
#!/bin/bash
for image_file in *.JPG
do
convert $image_file -set filename:size '%wx%h' ${image_file}_%[filename:size].png
done
Please, why must I call the name of a file in three different way depending on the context: image_file in the "for" statemente, $image_file as input file in convert, and ${input_file} in the output filename variable. It will be great to understand this!
Thanks all for your great help!
Re: output file name
Posted: 2010-09-28T17:34:40-07:00
by fmw42
rrodriguez wrote:Brackets in, quotation marks out! Following the last post by fmw42, this also works for me now:
Code: Select all
#!/bin/bash
for image_file in *.JPG
do
convert $image_file -set filename:size '%wx%h' ${image_file}_%[filename:size].png
done
Please, why must I call the name of a file in three different way depending on the context: image_file in the "for" statemente, $image_file as input file in convert, and ${input_file} in the output filename variable. It will be great to understand this!
Thanks all for your great help!
The quotes probably can be used. It was the missing brackets.
The image_file in the for statement, just assigns each file from *.JPG to the variable image_file.
The $image_file at the beginning of the convert uses the variable with each of your images as input to the convert.
The ${image_file}_ etc at the end assigns that name to the output.
But note, as it is, it also includes the .jpg in the name.
This is better:
#!/bin/bash
cd test1
filelist=`ls | grep '.jpg'`
for image_file in $filelist
do
inname=`convert $image_file -format "%t" info:`
convert $image_file -set filename:mysize "%wx%h" ../test2/${inname}_%[filename:mysize].png
done
Which then makes
lena2_128x128.png
lena3_128x128.png
lena_256x256.png
inname=`convert $image_file -format "%t" info:`
just gets the name part of the file without the suffix and assigns it to $inname variable.
see string format t at
http://www.imagemagick.org/script/escape.php
Re: output file name
Posted: 2010-09-28T20:09:16-07:00
by anthony
Also see
http://www.imagemagick.org/Usage/basics/#mogrify_not
Mogrify can not be used when also renaming the output file.
Re: output file name
Posted: 2010-11-22T11:25:05-07:00
by CptWacko
I got another question about the files output names...
Is it possible to use more than 1 digit for the image count ?
When converting a pdf to jpg, I'd like to have the files named image0001, image0002, etc. instead of image1, image2, etc.
Thanks for any replies !
Re: output file name
Posted: 2010-11-22T15:53:28-07:00
by fmw42
use _%04d
convert rose: rose: rose: tmp_%04d.png
generates:
tmp_0000.png
tmp_0001.png
tmp_0002.png
Re: output file name
Posted: 2010-11-22T19:32:15-07:00
by anthony
fmw42 wrote:#!/bin/bash
cd test1
filelist=`ls | grep '.jpg'`
for image_file in $filelist
do
inname=`convert $image_file -format "%t" info:`
convert $image_file -set filename:mysize "%wx%h" ../test2/${inname}_%[filename:mysize].png
done
You could include the %t in the 'filename:mysize' setting
Code: Select all
convert "$image_file" -set filename:myname '%t_%wx%h' "../test2/$[filename:myname].png"
I recommend quotes around the output filename to stop the shell trying to evaluate the $[...]
I also recommend quota around the input filename incase the filename has spaces in it!
Re: output file name
Posted: 2010-11-22T21:26:03-07:00
by anthony
Unfortunately there is no string formatting for the % escapes
As such %wx%h will not have any leading zeros
Re: output file name
Posted: 2010-11-24T07:56:51-07:00
by CptWacko
Thanks a lot for the replies !
