Legacy ImageMagick Discussions Archive

I'm so close, but the syntax must be off. I'm using the identify command to see the height & width of an image. I then need to see that as a variable so that it can be processed by an If/Then statement. I've tried the following things but they are all wrong. Does anyone know how to output the height & width (separately) so that I can process it with conditional logic?

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#!/bin/bash
identify sand.jpg -format "%f,%w,%h"
echo %w

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#!/bin/bash
identify sand.jpg -format "%f,%w,%h"
echo $%w

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#!/bin/bash
identify sand.jpg -format "%f,%w,%h"
echo $(%w)

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#!/bin/bash
identify sand.jpg -format "%f,%w,%h"
echo $(w)

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#!/bin/bash
identify sand.jpg -format "%f,%w,%h" > $newVariable
echo$newVariable

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#!/bin/bash
newVariable=identify sand.jpg -format "%f,%w,%h" 
echo$newVariable

try either

newVariable=`identify -format "%f,%w,%h" sand.jpg`

or

newVariable=`convert sand.jpg -format "%f,%w,%h"`

note these are not normal quotes, but slanted quotes - same key as the tilde - to the left of the 1 key

or

newVariable=$(convert sand.jpg -format "%f,%w,%h")

or

newVariable=$(identify -format "%f,%w,%h" sand.jpg)

but you will get 3 items in one variable, so you may want to make 3 variables to start

A special way of extracting three values (space separated) into three variables in bash is this special bash 'trick'

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read -r file width height <<< $( convert sand.jpg -format "%f %w %h" info:)
echo filename=$file
echo width=$width
echo height=$height

This only works with BASH, not an older bourne shell or ksh or zsh, php, perl etc. JUST BASH.
Other languages have other ways of parsing strings.

Legacy ImageMagick Discussions Archive

Identify command to output to Variable

Identify command to output to Variable

Re: Identify command to output to Variable

Re: Identify command to output to Variable