Question regarding convert -blur

[elkayein]

Hello,

This is probably trivial but I couldn't find an appropriate answer in the documentation. I am trying to understand an existing script that uses convert in this syntax

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convert -quality 100 -blur 10 xxx.jpg xxx.jpg

I see that blur has only one argument,10. Is this the radius? Does that mean the Sigma is 0? Because the documentation at http://www.imagemagick.org/script/comma ... s.php#blur tells me that Sigma is mandatory.

Thanks!

[snibgo]

That page says:

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-blur radius
-blur radius x sigma

This means you can provide either the radius alone, or the radius and sigma separated by "x".

And your command has arguments in the wrong order. It should be:

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convert xxx.jpg -quality 100 -blur 10 xxx.jpg