Legacy ImageMagick Discussions Archive

I want to replace the color in one image to another, while por. I am doing this using the following command:
This works fine. However, when I put that script in a quick bash sh file, the contents of which are:
and I run 'sh test.sh ffffff', I get the error "unable to open image `'#ff00ff'' and "no decode delegate for this image format `'#ff00ff''.

Does anyone have any ideas? I've tried checking the literature and the command line works great assuming no options, but i'm not sure if there's something stupid i'm doing.

too many quotes

try

#!/bin/bash
convert image1.png -fill "#$1" -opaque '#ff00ff' image2.png

Note you must use double quotes to resolve the variable

or

#!/bin/bash
color=$1
convert image1.png -fill "#$color" -opaque '#ff00ff' image2.png

Thanks for the response. I was able to get it working with the following set of programs:

the php program (which takes a 'GET' color of 6 hex values) (e.g. website.com/colorchange.php?color=ffffff) and the colorchange.sh command that worked Took me forever figuring out what quote levels worked. Nevertheless, it's working, thank you!