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sanderton
Post
by sanderton » 2006-07-26T09:32:16-07:00
I'm puzzled by the results that I'm getting when I run identify -verbose on the command line, and when calling colorSpace() from my C++ code.
The colorSpace() function returns RGBColorspace for a Greyscale image, but this is what I get from identify:
Code: Select all
Image: C:\Projects\testing\PSD\PSD_Greyscale.psd
Format: PSD (Adobe Photoshop bitmap)
Class: PseudoClass
Geometry: 1070x839
Type: Grayscale
Endianess: Undefined
Colorspace: Gray
Channel depth:
Gray: 8-bits
Channel statistics:
Gray:
Min: 20 (0.0784314)
Max: 254 (0.996078)
Mean: 93.5203 (0.366746)
Standard deviation: 48.7813 (0.191299)
Colors: 256
Histogram:
...
Version: ImageMagick 6.2.8 06/30/06 Q8 http://www.imagemagick.org
What do I need to do in the C++ code to correctly identify the image as Grayscale?
Thanks,
sanderton
magick
Site Admin
Posts: 11064 Joined: 2003-05-31T11:32:55-07:00
Post
by magick » 2006-07-26T11:44:15-07:00
Use
to return the image type. It will return GrayscaleType for a grayscale image.
sanderton
Post
by sanderton » 2006-07-27T08:17:44-07:00
Thanks, that helped.
But I'm still curious about the colorspace() function. I feel like I'm misunderstanding something here; why does the identify output indicate
Colorspace: Gray
when the colorspace() function returns RGBColorspace?